Prove that n2-n is even for every positive integer n.
 
                Answer: 
            
        - We have been asked to prove that n2 - n is even for every positive integer n.
- Before beginning, we have to understand the following
 Even × Even = Even
 Even - Even = Even
 Odd - Odd = Even
 Odd × Odd = Odd
 
- First, suppose n is odd:
 Now, n2 - n = (odd)2 - (odd)
 = odd × odd - odd
 = odd - odd
 = Even
- Second, suppose n is even:
 Now, n2 - n = (even)2 - (even)
 = even × even - even
 = even - even
 = even
- Therefore, n2 - n is even for every positive integer n.
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