In the parallellogram ABCD, the sum of angle bisectors of two adjacent angles is _______.
![](https://www.edugain.com/egdraw/draw.php?num=1&sx=500&sy=150&A1=shape:polygon;points:100,0,140,120,340,120,300,0, 100, 0, 230, 90, 300, 0;t;textc:[-10.0]A,[-20.0]B, C,D,,[0.15]O )
Answer:
90°
- Following figure shows the parallelogram ABCD,
Let's assume, AO and DO are the angle bisectors of the adjacent angles ∠A and ∠D respectively.
Therefore, ∠DAO = ∠A/2,
∠ADO = ∠D/2. - We know that the adjacent angles in a parallelogram are supplementary as they are formed by a straight line (e.g. AD) intersecting two paralle lines (e.g. AB and CD).
Therefore sum of the adjacent angles equals to 180°.
∠A + ∠D = 180° -----(1) - Now, the sum of angle bisectors of the adjacent angles ∠A and ∠D = ∠DAO + ∠ADO
= ∠A/2 + ∠D/2
= (∠A + ∠D)/2
= 180/2
= 90° - Hence, the sum of angle bisectors of two adjacent angles is 90°.