In a rectangle ABCD, E, F, G, and H are the midpoints of the four sides, what kind of shape is represented by EFGH.
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Answer: Rhombus
Step by Step Explanation: - The following figure shows the rectangle ABCD,
![](https://www.edugain.com/egdraw/draw.php?num=2&sx=200&sy=160&x0=20&y0=20&A1=shape:polygon;points:0,0,150,0,150,100,0,100;textc:A,B,[0.15]C,[0.15]D&A2=shape:polygon;points:0,50,75,0,150,50,75,100;textc:[-8.5]H,E,[2.5]F,[0.15]G )
Let's assume the length and breadth of the rectangle ABCD be a and b respectively. - In ΔGDH, DG = = ,
DH = = [Since, G and H are the midpoints of the sides CD and DA respectively.]
∠D = 90° [Since, ABCD is a rectangle.]
GH2 = DG2 + DH2 [By the pythagorean theorem.]
⇒ GH2 = ( )2 + ( )2
Similarly, HE2 = EF2 = FG2 = ( )2 + ( )2
and hence, HE2 = EF2 = FG2 = GH2,
or HE = EF = FG = GH - We know that quadrilateral with all four sides equal is rhombus. Therefore, EFGH is a Rhombus.