If x + y - 4t = 0 then find the value of ^@ \dfrac{ x } { x - 2t } + \dfrac{ 2t } { y - 2t} ^@.
Answer:
1
- We are given x + y - 4t = 0
It can also be written as: (x - 2t) + (y - 2t) = 0
or (x - 2t) = -(y - 2t) - The above step tells us that we may replace (x - 2t) with -(y - 2t) wherever needed.
- We need to find the value of ^@ \dfrac{ x } { x - 2t } + \dfrac{ 2t } { y - 2t} ^@ which is equal to:
+x -(y - 2t) 2t y - 2t
=-x + 2t y - 2t
=-(x - 2t) (y - 2t) - As we know that (x - 2t) = -(y - 2t), the answer to the above question becomes 1.