How many 8-digit whole numbers are there in the base-10 system?


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Answer:

90000000 numbers

Step by Step Explanation:
  1. All 8-digit numbers are smaller than any 9-digit numbers. Therefore, all the 8-digit numbers will lie between the largest 9-digit number and the smallest 7-digit number.
  2. Hence, the total number of 8-digit numbers
    = Smallest 9-digit number - Largest 7-digit number - 1
     (We need to subtract 1 as both the numbers are not 8-digit numbers, and therefore, should not be counted.)
    = 100000000 - 9999999 -1
    = 90000000
  3. Hence, there are a total of 90000000 8-digit numbers in the base-10 system.

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