Find the Pythagorean triplet whose smallet member is ^@12.^@


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Answer:

^@ (12,35,37) ^@

Step by Step Explanation:
  1. For every natural number ^@m > 1 ^@, ^@ (2m,m^2-1,m^2 +1) ^@ is a Pythagorean triplet.
    Putting ^@2m = 12 ^@, we get ^@m = 6. ^@

    Thus,
    ^@ m^2-1 = 6^2 - 1 = 35 ^@
    ^@ m^2+1 = 6^2 + 1 = 37 ^@
  2. Hence, ^@ (12,35,37) ^@ is a Pythagorean triplet.

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