Assume you roll a die 2 times. What is the probability that you will get exactly one 6?  
 
                    
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                Answer:  
  
                Step by Step Explanation: - According to the question, a die rolled 2 times 
 So, the Sample Space(S) is { (i, j): i, j = 1, 2, 3, 4, 5, 6 }
- Total number of outcomes in sample space n(S) = 6 × 6 = 36
- Let E be the event that you will get exactly one 6.
 Number of outcomes in which '6' appears only on the first throw = 1 × 5 = 5
 As the die is thrown 2 times, '6' (appearing exactly once) can appear on any of the 2 throws.
 Therefore, the total number of outcomes when 6 appears exactly once, n(E) = 2 × 5 = 10
- Probability, P(E) =     =    
- Therefore, the probability of getting exactly one 6 is     .