AC is the diameter of the semicircle and BD is perpendicular to AC. If AB = 8 cm and BC = 2 cm, find the length of BD.
![](https://www.edugain.com/egdraw/draw.php?num=3&sx=310&sy=165&x0=155&y0=20&A1=shape:pcircle;cx:0;cy:0;r:250;s:180;e:0&A2=shape:line;x1:-125;y1:0;x2:125;y2:0;tc1:A;tc2:C&A3=shape:line;x1:75;y1:0;x2:75;y2:100;tc1:B;tc2:[0.15]D )
Answer:
4 cm
- The following figure shows the semicircle with the diameter AC,
According to the question, AB = 8 cm, and BC = 2 cm.
The diameter(AC) of the semicircle = AB + BC
= 8 + 2
= 10 cm - Let's draw a line OD from the center of the semicircle, as shown in the following figure,
The line OD, OA and OC are the radii of the semicircle.
Therefore, OD = OA = OC =AC 2
=10 2
= 5 cm - Now, OB = OC - BC
= 5 - 2
= 3 cm - In ΔOBD, ∠OBD = 90°
BD2 = OD2 - OB2 [By the Pythagorean theorem]
⇒ BD2 = 52 - 32
⇒ BD2 = 16
⇒ BD2 = 42
⇒ BD = 4 cm - Hence, the length of the BD is 4 cm.